What are the solutions to the equation 2x^2-10x-1=0 ?

The solutions to the equation 2x^2-10x-1=0 are x=(5+3sqrt(3))/2 ,x=(5-3sqrt(3))/2

Find the zeros of 2x^2-10x-1=0

The zeros of 2x^2-10x-1=0 are x=(5+3sqrt(3))/2 ,x=(5-3sqrt(3))/2

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2 x^{2} - 10 x - 1 = 0

x = \frac{5 + 3 3}{2}, x = \frac{5 - 3 3}{2}

Decimal Notation

x = 5.09807 \dots, x = - 0.09807 \dots

Solution steps

2 x^{2} - 10 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 (- 1) = 63

x_{1, 2} = \frac{- ( - 10 ) \pm 6 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6 3}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 6 3}{2 \cdot 2}

x = \frac{- ( - 10 ) + 6 3}{2 \cdot 2} : \frac{5 + 3 3}{2}

x = \frac{- ( - 10 ) - 6 3}{2 \cdot 2} : \frac{5 - 3 3}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 3 3}{2}, x = \frac{5 - 3 3}{2}

- x^{2} = 225

x^{2} - 9 = 5

(x + 5)^{2} = 8

x, x f x - y f y = 0

5 y^{2} = 125

What are the solutions to the equation 2x^2-10x-1=0 ?
The solutions to the equation 2x^2-10x-1=0 are x=(5+3sqrt(3))/2 ,x=(5-3sqrt(3))/2
Find the zeros of 2x^2-10x-1=0
The zeros of 2x^2-10x-1=0 are x=(5+3sqrt(3))/2 ,x=(5-3sqrt(3))/2