What are the solutions to the equation -1/4 b^2-b^2=-1 ?

The solutions to the equation -1/4 b^2-b^2=-1 are b= 2/(sqrt(5)),b=-2/(sqrt(5))

Find the zeros of -1/4 b^2-b^2=-1

The zeros of -1/4 b^2-b^2=-1 are b= 2/(sqrt(5)),b=-2/(sqrt(5))

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- \frac{1}{4} b^{2} - b^{2} = - 1

b = \frac{2}{5}, b = - \frac{2}{5}

Decimal Notation

b = 0.89442 \dots, b = - 0.89442 \dots

Solution steps

- \frac{1}{4} b^{2} - b^{2} = - 1

Multiply both sides by

4

- b^{2} - 4 b^{2} = - 4

- 5 b^{2} = - 4

Divide both sides by

- 5

b^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{4}{5}, b = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

b = \frac{2}{5}, b = - \frac{2}{5}

6 x - 8 = 2 x^{2}

6 x - 12 x^{2} = 0

3 q^{2} - 300 q - 112500 = 0

x^{2} + 16 x + 74 = 0

x^{2} + (x + 3)^{2} = 117

What are the solutions to the equation -1/4 b^2-b^2=-1 ?
The solutions to the equation -1/4 b^2-b^2=-1 are b= 2/(sqrt(5)),b=-2/(sqrt(5))
Find the zeros of -1/4 b^2-b^2=-1
The zeros of -1/4 b^2-b^2=-1 are b= 2/(sqrt(5)),b=-2/(sqrt(5))