What are the solutions to the equation x-2x^2+7=0 ?

The solutions to the equation x-2x^2+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4

Find the zeros of x-2x^2+7=0

The zeros of x-2x^2+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4

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x - 2 x^{2} + 7 = 0

x = - \frac{- 1 + 57}{4}, x = \frac{1 + 57}{4}

Decimal Notation

x = - 1.63745 \dots, x = 2.13745 \dots

Solution steps

x - 2 x^{2} + 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 7 = 57

x_{1, 2} = \frac{- 1 \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 57}{2 ( - 2 )}, x_{2} = \frac{- 1 - 57}{2 ( - 2 )}

x = \frac{- 1 + 57}{2 ( - 2 )} : - \frac{- 1 + 57}{4}

x = \frac{- 1 - 57}{2 ( - 2 )} : \frac{1 + 57}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 57}{4}, x = \frac{1 + 57}{4}

- x^{2} = 1 - \frac{3 x ( x - 1 )}{2}

b^{2} - 6 = 5 an

x^{2} + 16 x = - 44

x^{2} + 16 x = - 51

3 x^{2} + 20 x + 32 = 0

What are the solutions to the equation x-2x^2+7=0 ?
The solutions to the equation x-2x^2+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4
Find the zeros of x-2x^2+7=0
The zeros of x-2x^2+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4