What are the solutions to the equation x^2+21x+54=0 ?

The solutions to the equation x^2+21x+54=0 are x=-3,x=-18

Find the zeros of x^2+21x+54=0

The zeros of x^2+21x+54=0 are x=-3,x=-18

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x^{2} + 21 x + 54 = 0

x = - 3, x = - 18

Solution steps

x^{2} + 21 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 54 = 15

x_{1, 2} = \frac{- 21 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 21 + 15}{2 \cdot 1}, x_{2} = \frac{- 21 - 15}{2 \cdot 1}

x = \frac{- 21 + 15}{2 \cdot 1} : - 3

x = \frac{- 21 - 15}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = - 3, x = - 18

200 = 0.1 x^{2} + 2.155 x + 19.985

9 k^{2} + 21 = 25

(k - 1) x^{2} + (k + 4) x + 25 = 0, k \neq = 1

x, f = x^{2}

5 x^{2} - 26 x - 24 = 0

What are the solutions to the equation x^2+21x+54=0 ?
The solutions to the equation x^2+21x+54=0 are x=-3,x=-18
Find the zeros of x^2+21x+54=0
The zeros of x^2+21x+54=0 are x=-3,x=-18