What are the solutions to the equation 9k^2+21=25 ?

The solutions to the equation 9k^2+21=25 are k= 2/3 ,k=-2/3

Find the zeros of 9k^2+21=25

The zeros of 9k^2+21=25 are k= 2/3 ,k=-2/3

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9 k^{2} + 21 = 25

k = \frac{2}{3}, k = - \frac{2}{3}

Decimal Notation

k = 0.66666 \dots, k = - 0.66666 \dots

Solution steps

9 k^{2} + 21 = 25

Move

21

to the right side

9 k^{2} = 4

Divide both sides by

9

k^{2} = \frac{4}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = \frac{4}{9}, k = - \frac{4}{9}

\frac{4}{9} = \frac{2}{3}

- \frac{4}{9} = - \frac{2}{3}

k = \frac{2}{3}, k = - \frac{2}{3}

(k - 1) x^{2} + (k + 4) x + 25 = 0, k \neq = 1

x, f = x^{2}

5 x^{2} - 26 x - 24 = 0

0 = x^{2} + x + 4

- 2 x^{2} = 4 x

What are the solutions to the equation 9k^2+21=25 ?
The solutions to the equation 9k^2+21=25 are k= 2/3 ,k=-2/3
Find the zeros of 9k^2+21=25
The zeros of 9k^2+21=25 are k= 2/3 ,k=-2/3