What are the solutions to the equation 0=x^2+x+4 ?

The solutions to the equation 0=x^2+x+4 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2

Find the zeros of 0=x^2+x+4

The zeros of 0=x^2+x+4 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + x + 4

x = - \frac{1}{2} + i \frac{15}{2}, x = - \frac{1}{2} - i \frac{15}{2}

Solution steps

0 = x^{2} + x + 4

Switch sides

x^{2} + x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 4 : 15 i

x_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 15 i}{2 \cdot 1}

x = \frac{- 1 + 15 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{15}{2}

x = \frac{- 1 - 15 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{15}{2}, x = - \frac{1}{2} - i \frac{15}{2}

- 2 x^{2} = 4 x

x + 7 + 2 x - 3 = x^{2}

(3 - x)^{2} + 4 - 2 (3 - x) = x

3 x^{2} + 6 x = 3

x^{2} - x - \frac{7}{4} = 0

What are the solutions to the equation 0=x^2+x+4 ?
The solutions to the equation 0=x^2+x+4 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2
Find the zeros of 0=x^2+x+4
The zeros of 0=x^2+x+4 are x=-1/2+i(sqrt(15))/2 ,x=-1/2-i(sqrt(15))/2