What are the solutions to the equation R^2=(4)^2+(3)^2 ?

The solutions to the equation R^2=(4)^2+(3)^2 are R=5,R=-5

Find the zeros of R^2=(4)^2+(3)^2

The zeros of R^2=(4)^2+(3)^2 are R=5,R=-5

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R^{2} = (4)^{2} + (3)^{2}

R = 5, R = - 5

Solution steps

R^{2} = (4)^{2} + (3)^{2}

Simplify

4^{2} + 3^{2} : 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

R = 25, R = - 25

25 = 5

- 25 = - 5

R = 5, R = - 5

5 x^{2} = 10 x - 4

\frac{1}{8} - t^{2} = 0

2 x^{2} + 3 x = 77

- 4.9 x^{2} + 13 x + 18 = 0

x^{2} - 2 x + 1 = 0

What are the solutions to the equation R^2=(4)^2+(3)^2 ?
The solutions to the equation R^2=(4)^2+(3)^2 are R=5,R=-5
Find the zeros of R^2=(4)^2+(3)^2
The zeros of R^2=(4)^2+(3)^2 are R=5,R=-5