What are the solutions to the equation 16m^2-25=0 ?

The solutions to the equation 16m^2-25=0 are m= 5/4 ,m=-5/4

Find the zeros of 16m^2-25=0

The zeros of 16m^2-25=0 are m= 5/4 ,m=-5/4

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16 m^{2} - 25 = 0

m = \frac{5}{4}, m = - \frac{5}{4}

Decimal Notation

m = 1.25, m = - 1.25

Solution steps

16 m^{2} - 25 = 0

Move

25

to the right side

16 m^{2} = 25

Divide both sides by

16

m^{2} = \frac{25}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{25}{16}, m = - \frac{25}{16}

\frac{25}{16} = \frac{5}{4}

- \frac{25}{16} = - \frac{5}{4}

m = \frac{5}{4}, m = - \frac{5}{4}

(19 x - 2)^{2} - 3 (19 x - 2) - 10 = 0

x^{2} + 2 = 5 (x^{2} + 1)

x^{2} + 3 = 2 x^{2} - 1

(x - 6)^{2} - 1 = 0

2 x (x - 2) = 9

What are the solutions to the equation 16m^2-25=0 ?
The solutions to the equation 16m^2-25=0 are m= 5/4 ,m=-5/4
Find the zeros of 16m^2-25=0
The zeros of 16m^2-25=0 are m= 5/4 ,m=-5/4