What are the solutions to the equation 4v^2+4=40 ?

The solutions to the equation 4v^2+4=40 are v=3,v=-3

Find the zeros of 4v^2+4=40

The zeros of 4v^2+4=40 are v=3,v=-3

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4 v^{2} + 4 = 40

v = 3, v = - 3

Solution steps

4 v^{2} + 4 = 40

Move

4

to the right side

4 v^{2} = 36

Divide both sides by

4

v^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 9, v = - 9

9 = 3

- 9 = - 3

v = 3, v = - 3

(32 - x)^{2} + (16 - x)^{2} = x^{2}

5 x^{2} + 40 x = - 75

x^{2} - x + \frac{1}{8} = 0

x, 0 = x (1 - x) + m - h x

6 x^{2} - 5 x + 4 = 4 (3 x^{2} - 2 x + 1)

What are the solutions to the equation 4v^2+4=40 ?
The solutions to the equation 4v^2+4=40 are v=3,v=-3
Find the zeros of 4v^2+4=40
The zeros of 4v^2+4=40 are v=3,v=-3