What are the solutions to the equation solvefor y,y^2=e^{2t}+k ?

The solutions to the equation solvefor y,y^2=e^{2t}+k are y=sqrt(e^{2t)+k},y=-sqrt(e^{2t)+k}

Find the zeros of solvefor y,y^2=e^{2t}+k

The zeros of solvefor y,y^2=e^{2t}+k are y=sqrt(e^{2t)+k},y=-sqrt(e^{2t)+k}

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solve for

y, y^{2} = e^{2 t} + k

y = e^{2 t} + k, y = - e^{2 t} + k

Solution steps

y^{2} = e^{2 t} + k

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = e^{2 t} + k, y = - e^{2 t} + k

0.4 x^{2} + 0.242 x - 0.042 = 0

x + 2 (x - 3)^{2} + 2 = 3 (x + 2)^{2}

0 = - x^{2} + 6 x - 15

x, x^{2} + 3 x = 0

y^{2} - 12 y = - 34

What are the solutions to the equation solvefor y,y^2=e^{2t}+k ?
The solutions to the equation solvefor y,y^2=e^{2t}+k are y=sqrt(e^{2t)+k},y=-sqrt(e^{2t)+k}
Find the zeros of solvefor y,y^2=e^{2t}+k
The zeros of solvefor y,y^2=e^{2t}+k are y=sqrt(e^{2t)+k},y=-sqrt(e^{2t)+k}