What are the solutions to the equation y^2-12y=-34 ?

The solutions to the equation y^2-12y=-34 are y=6+sqrt(2),y=6-sqrt(2)

Find the zeros of y^2-12y=-34

The zeros of y^2-12y=-34 are y=6+sqrt(2),y=6-sqrt(2)

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y^{2} - 12 y = - 34

y = 6 + 2, y = 6 - 2

Decimal Notation

y = 7.41421 \dots, y = 4.58578 \dots

Solution steps

y^{2} - 12 y = - 34

Move

34

to the left side

y^{2} - 12 y + 34 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 34 = 22

y_{1, 2} = \frac{- ( - 12 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 12 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 12 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 12 ) + 2 2}{2 \cdot 1} : 6 + 2

y = \frac{- ( - 12 ) - 2 2}{2 \cdot 1} : 6 - 2

The solutions to the quadratic equation are:

y = 6 + 2, y = 6 - 2

(7 + 2 x) (3 + 2 x) - 21 = 56

0 = 40 + 5 x - 4.9 x^{2}

x, x^{2} + y^{2} = a

2 x (x - 2) = 6 x^{2} - 5 x

2 w^{2} - 5 w = 33

What are the solutions to the equation y^2-12y=-34 ?
The solutions to the equation y^2-12y=-34 are y=6+sqrt(2),y=6-sqrt(2)
Find the zeros of y^2-12y=-34
The zeros of y^2-12y=-34 are y=6+sqrt(2),y=6-sqrt(2)