What are the solutions to the equation 2w^2-5w=33 ?

The solutions to the equation 2w^2-5w=33 are w= 11/2 ,w=-3

Find the zeros of 2w^2-5w=33

The zeros of 2w^2-5w=33 are w= 11/2 ,w=-3

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2 w^{2} - 5 w = 33

w = \frac{11}{2}, w = - 3

Decimal Notation

w = 5.5, w = - 3

Solution steps

2 w^{2} - 5 w = 33

Move

33

to the left side

2 w^{2} - 5 w - 33 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 33 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 33) = 17

w_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 2}, w_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 2}

w = \frac{- ( - 5 ) + 17}{2 \cdot 2} : \frac{11}{2}

w = \frac{- ( - 5 ) - 17}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = \frac{11}{2}, w = - 3

0.8 x^{2} - 24 x + 200 = 0

x^{2} + 12 x + 144 = 0

10 x^{2} = 360

6 x^{2} - 11 x = 10

2 x^{2} + 5 x - 1

What are the solutions to the equation 2w^2-5w=33 ?
The solutions to the equation 2w^2-5w=33 are w= 11/2 ,w=-3
Find the zeros of 2w^2-5w=33
The zeros of 2w^2-5w=33 are w= 11/2 ,w=-3