What are the solutions to the equation 15x^2-12x-9=0 ?

The solutions to the equation 15x^2-12x-9=0 are x=(2+sqrt(19))/5 ,x=(2-sqrt(19))/5

Find the zeros of 15x^2-12x-9=0

The zeros of 15x^2-12x-9=0 are x=(2+sqrt(19))/5 ,x=(2-sqrt(19))/5

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15 x^{2} - 12 x - 9 = 0

x = \frac{2 + 19}{5}, x = \frac{2 - 19}{5}

Decimal Notation

x = 1.27177 \dots, x = - 0.47177 \dots

Solution steps

15 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 15 ( - 9 )}{2 \cdot 15}

(- 12)^{2} - 4 \cdot 15 (- 9) = 619

x_{1, 2} = \frac{- ( - 12 ) \pm 6 19}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 19}{2 \cdot 15}, x_{2} = \frac{- ( - 12 ) - 6 19}{2 \cdot 15}

x = \frac{- ( - 12 ) + 6 19}{2 \cdot 15} : \frac{2 + 19}{5}

x = \frac{- ( - 12 ) - 6 19}{2 \cdot 15} : \frac{2 - 19}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 19}{5}, x = \frac{2 - 19}{5}

121 = t^{2}

- 16 t^{2} + 400 = 0

x, - 2 x^{2} - 5 x + 27 = 0

9 y^{2} - y + 4 = 0

(x + 8)^{2} = 86

What are the solutions to the equation 15x^2-12x-9=0 ?
The solutions to the equation 15x^2-12x-9=0 are x=(2+sqrt(19))/5 ,x=(2-sqrt(19))/5
Find the zeros of 15x^2-12x-9=0
The zeros of 15x^2-12x-9=0 are x=(2+sqrt(19))/5 ,x=(2-sqrt(19))/5