What are the solutions to the equation -16t^2+400=0 ?

The solutions to the equation -16t^2+400=0 are t=5,t=-5

Find the zeros of -16t^2+400=0

The zeros of -16t^2+400=0 are t=5,t=-5

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- 16 t^{2} + 400 = 0

t = 5, t = - 5

Solution steps

- 16 t^{2} + 400 = 0

Move

400

to the right side

- 16 t^{2} = - 400

Divide both sides by

- 16

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

x, - 2 x^{2} - 5 x + 27 = 0

9 y^{2} - y + 4 = 0

(x + 8)^{2} = 86

6 x^{2} + 2 x = 0

4 = 3 x^{2} + 5 x - 8

What are the solutions to the equation -16t^2+400=0 ?
The solutions to the equation -16t^2+400=0 are t=5,t=-5
Find the zeros of -16t^2+400=0
The zeros of -16t^2+400=0 are t=5,t=-5