What are the solutions to the equation 4=3x^2+5x-8 ?

The solutions to the equation 4=3x^2+5x-8 are x= 4/3 ,x=-3

Find the zeros of 4=3x^2+5x-8

The zeros of 4=3x^2+5x-8 are x= 4/3 ,x=-3

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4 = 3 x^{2} + 5 x - 8

x = \frac{4}{3}, x = - 3

Decimal Notation

x = 1.33333 \dots, x = - 3

Solution steps

4 = 3 x^{2} + 5 x - 8

Switch sides

3 x^{2} + 5 x - 8 = 4

Move

4

to the left side

3 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 12) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 3}, x_{2} = \frac{- 5 - 13}{2 \cdot 3}

x = \frac{- 5 + 13}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 5 - 13}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 3

4 x^{2} + 4 x = 33

x^{2} + (- 8) x + 15 = 0

0 = 2 x^{2} + 6 x - 3

4 x^{2} = - 32

4 x^{2} = 225

What are the solutions to the equation 4=3x^2+5x-8 ?
The solutions to the equation 4=3x^2+5x-8 are x= 4/3 ,x=-3
Find the zeros of 4=3x^2+5x-8
The zeros of 4=3x^2+5x-8 are x= 4/3 ,x=-3