What are the solutions to the equation 4x^2=-32 ?

The solutions to the equation 4x^2=-32 are x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of 4x^2=-32

The zeros of 4x^2=-32 are x=2sqrt(2)i,x=-2sqrt(2)i

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4 x^{2} = - 32

x = 22 i, x = - 22 i

Solution steps

4 x^{2} = - 32

Divide both sides by

4

x^{2} = - 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 8, x = - - 8

- 8 = 22 i

- - 8 = - 22 i

x = 22 i, x = - 22 i

4 x^{2} = 225

x^{2} - 10 x + 30 = 9

x (x + 3) - 5 x = 3

0 = 3 x^{2} - 4 x - 2

4 x^{2} = 10 x

What are the solutions to the equation 4x^2=-32 ?
The solutions to the equation 4x^2=-32 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of 4x^2=-32
The zeros of 4x^2=-32 are x=2sqrt(2)i,x=-2sqrt(2)i