What are the solutions to the equation -3x(4x+2)=2x+1 ?

The solutions to the equation -3x(4x+2)=2x+1 are x=-1/2 ,x=-1/6

Find the zeros of -3x(4x+2)=2x+1

The zeros of -3x(4x+2)=2x+1 are x=-1/2 ,x=-1/6

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- 3 x (4 x + 2) = 2 x + 1

x = - \frac{1}{2}, x = - \frac{1}{6}

Decimal Notation

x = - 0.5, x = - 0.16666 \dots

Solution steps

- 3 x (4 x + 2) = 2 x + 1

Expand

- 3 x (4 x + 2) : - 12 x^{2} - 6 x

- 12 x^{2} - 6 x = 2 x + 1

Move

1

to the left side

- 12 x^{2} - 6 x - 1 = 2 x

Move

2 x

to the left side

- 12 x^{2} - 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 12 ) ( - 1 )}{2 ( - 12 )}

(- 8)^{2} - 4 (- 12) (- 1) = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 ( - 12 )}, x_{2} = \frac{- ( - 8 ) - 4}{2 ( - 12 )}

x = \frac{- ( - 8 ) + 4}{2 ( - 12 )} : - \frac{1}{2}

x = \frac{- ( - 8 ) - 4}{2 ( - 12 )} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{1}{6}

4 x^{2} - 72 x = - 68

- 5 x - x^{2} = 84

(6 - x) (2 - x) + 5 = 0

6 x^{2} + 6 x - 13 = 0

2 x (x - 6) = 3

What are the solutions to the equation -3x(4x+2)=2x+1 ?
The solutions to the equation -3x(4x+2)=2x+1 are x=-1/2 ,x=-1/6
Find the zeros of -3x(4x+2)=2x+1
The zeros of -3x(4x+2)=2x+1 are x=-1/2 ,x=-1/6