What are the solutions to the equation 0=2x^2-11x-40 ?

The solutions to the equation 0=2x^2-11x-40 are x=8,x=-5/2

Find the zeros of 0=2x^2-11x-40

The zeros of 0=2x^2-11x-40 are x=8,x=-5/2

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0 = 2 x^{2} - 11 x - 40

x = 8, x = - \frac{5}{2}

Decimal Notation

x = 8, x = - 2.5

Solution steps

0 = 2 x^{2} - 11 x - 40

Switch sides

2 x^{2} - 11 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 40) = 21

x_{1, 2} = \frac{- ( - 11 ) \pm 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 21}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 21}{2 \cdot 2}

x = \frac{- ( - 11 ) + 21}{2 \cdot 2} : 8

x = \frac{- ( - 11 ) - 21}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{5}{2}

a, (a - b)^{2} = 9

x^{2} + 4 x + 4 = 36

x, 4 x^{2} + k x + 16 = 0

4 x^{2} + 36 x + 9 = 0

4 x^{2} = 3 x - 1

What are the solutions to the equation 0=2x^2-11x-40 ?
The solutions to the equation 0=2x^2-11x-40 are x=8,x=-5/2
Find the zeros of 0=2x^2-11x-40
The zeros of 0=2x^2-11x-40 are x=8,x=-5/2