What are the solutions to the equation 4x^2+36x+9=0 ?

The solutions to the equation 4x^2+36x+9=0 are x=(3(2sqrt(2)-3))/2 ,x=-(3(3+2sqrt(2)))/2

Find the zeros of 4x^2+36x+9=0

The zeros of 4x^2+36x+9=0 are x=(3(2sqrt(2)-3))/2 ,x=-(3(3+2sqrt(2)))/2

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4 x^{2} + 36 x + 9 = 0

x = \frac{3 ( 2 2 - 3 )}{2}, x = - \frac{3 ( 3 + 2 2 )}{2}

Decimal Notation

x = - 0.25735 \dots, x = - 8.74264 \dots

Solution steps

4 x^{2} + 36 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 9 = 242

x_{1, 2} = \frac{- 36 \pm 24 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 24 2}{2 \cdot 4}, x_{2} = \frac{- 36 - 24 2}{2 \cdot 4}

x = \frac{- 36 + 24 2}{2 \cdot 4} : \frac{3 ( 2 2 - 3 )}{2}

x = \frac{- 36 - 24 2}{2 \cdot 4} : - \frac{3 ( 3 + 2 2 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 2 - 3 )}{2}, x = - \frac{3 ( 3 + 2 2 )}{2}

4 x^{2} = 3 x - 1

x^{2} + 68 = - 4 x

25 = (x - 11)^{2}

(2 m - 1) (m + 3) = 3

x^{2} + 5 x + 2 = 3 x - 4

What are the solutions to the equation 4x^2+36x+9=0 ?
The solutions to the equation 4x^2+36x+9=0 are x=(3(2sqrt(2)-3))/2 ,x=-(3(3+2sqrt(2)))/2
Find the zeros of 4x^2+36x+9=0
The zeros of 4x^2+36x+9=0 are x=(3(2sqrt(2)-3))/2 ,x=-(3(3+2sqrt(2)))/2