What are the solutions to the equation (2m-1)(m+3)=3 ?

The solutions to the equation (2m-1)(m+3)=3 are m=(-5+sqrt(73))/4 ,m=(-5-sqrt(73))/4

Find the zeros of (2m-1)(m+3)=3

The zeros of (2m-1)(m+3)=3 are m=(-5+sqrt(73))/4 ,m=(-5-sqrt(73))/4

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(2 m - 1) (m + 3) = 3

m = \frac{- 5 + 73}{4}, m = \frac{- 5 - 73}{4}

Decimal Notation

m = 0.88600 \dots, m = - 3.38600 \dots

Solution steps

(2 m - 1) (m + 3) = 3

Expand

(2 m - 1) (m + 3) : 2 m^{2} + 5 m - 3

2 m^{2} + 5 m - 3 = 3

Move

3

to the left side

2 m^{2} + 5 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 6) = 73

m_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 5 + 73}{2 \cdot 2}, m_{2} = \frac{- 5 - 73}{2 \cdot 2}

m = \frac{- 5 + 73}{2 \cdot 2} : \frac{- 5 + 73}{4}

m = \frac{- 5 - 73}{2 \cdot 2} : \frac{- 5 - 73}{4}

The solutions to the quadratic equation are:

m = \frac{- 5 + 73}{4}, m = \frac{- 5 - 73}{4}

x^{2} + 5 x + 2 = 3 x - 4

- x^{2} - 4 x + 65 = 7

m^{2} + 6 m = - 109

- 4 x - 12 = - x^{2}

6 x^{2} - 48 x - 1374 = 0

What are the solutions to the equation (2m-1)(m+3)=3 ?
The solutions to the equation (2m-1)(m+3)=3 are m=(-5+sqrt(73))/4 ,m=(-5-sqrt(73))/4
Find the zeros of (2m-1)(m+3)=3
The zeros of (2m-1)(m+3)=3 are m=(-5+sqrt(73))/4 ,m=(-5-sqrt(73))/4