What are the solutions to the equation 7x^2+3x=7 ?

The solutions to the equation 7x^2+3x=7 are x=(-3+sqrt(205))/(14),x=(-3-sqrt(205))/(14)

Find the zeros of 7x^2+3x=7

The zeros of 7x^2+3x=7 are x=(-3+sqrt(205))/(14),x=(-3-sqrt(205))/(14)

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7 x^{2} + 3 x = 7

x = \frac{- 3 + 205}{14}, x = \frac{- 3 - 205}{14}

Decimal Notation

x = 0.80841 \dots, x = - 1.23698 \dots

Solution steps

7 x^{2} + 3 x = 7

Move

7

to the left side

7 x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 7 ( - 7 )}{2 \cdot 7}

3^{2} - 4 \cdot 7 (- 7) = 205

x_{1, 2} = \frac{- 3 \pm 205}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 3 + 205}{2 \cdot 7}, x_{2} = \frac{- 3 - 205}{2 \cdot 7}

x = \frac{- 3 + 205}{2 \cdot 7} : \frac{- 3 + 205}{14}

x = \frac{- 3 - 205}{2 \cdot 7} : \frac{- 3 - 205}{14}

The solutions to the quadratic equation are:

x = \frac{- 3 + 205}{14}, x = \frac{- 3 - 205}{14}

- 43 = 5 - 3 b^{2}

x, x^{2} - x y + y^{2} - 7 = 0

4 x^{2} - 5 (2 x - 1) = 0

x^{2} - 14 = - 5 - 5

k^{2} + 6 k - 16 = 0

What are the solutions to the equation 7x^2+3x=7 ?
The solutions to the equation 7x^2+3x=7 are x=(-3+sqrt(205))/(14),x=(-3-sqrt(205))/(14)
Find the zeros of 7x^2+3x=7
The zeros of 7x^2+3x=7 are x=(-3+sqrt(205))/(14),x=(-3-sqrt(205))/(14)