What are the solutions to the equation a^2+24a+135=0 ?

The solutions to the equation a^2+24a+135=0 are a=-9,a=-15

Find the zeros of a^2+24a+135=0

The zeros of a^2+24a+135=0 are a=-9,a=-15

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a^{2} + 24 a + 135 = 0

a = - 9, a = - 15

Solution steps

a^{2} + 24 a + 135 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 135}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 135 = 6

a_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 24 + 6}{2 \cdot 1}, a_{2} = \frac{- 24 - 6}{2 \cdot 1}

a = \frac{- 24 + 6}{2 \cdot 1} : - 9

a = \frac{- 24 - 6}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

a = - 9, a = - 15

5 x^{2} + 23 x = 10

4 z^{2} + 14 z - 3 = 12 z

(2 x + 4)^{2} - 5 = 31

x^{2} - 3 (x + 2) + 8 = 0

(3 x - 4) (2 x + 3) = 0

What are the solutions to the equation a^2+24a+135=0 ?
The solutions to the equation a^2+24a+135=0 are a=-9,a=-15
Find the zeros of a^2+24a+135=0
The zeros of a^2+24a+135=0 are a=-9,a=-15