What are the solutions to the equation 4z^2+14z-3=12z ?

The solutions to the equation 4z^2+14z-3=12z are z=(-1+sqrt(13))/4 ,z=-(1+sqrt(13))/4

Find the zeros of 4z^2+14z-3=12z

The zeros of 4z^2+14z-3=12z are z=(-1+sqrt(13))/4 ,z=-(1+sqrt(13))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 z^{2} + 14 z - 3 = 12 z

z = \frac{- 1 + 13}{4}, z = - \frac{1 + 13}{4}

Decimal Notation

z = 0.65138 \dots, z = - 1.15138 \dots

Solution steps

4 z^{2} + 14 z - 3 = 12 z

Move

12 z

to the left side

4 z^{2} + 2 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 3) = 213

z_{1, 2} = \frac{- 2 \pm 2 13}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- 2 + 2 13}{2 \cdot 4}, z_{2} = \frac{- 2 - 2 13}{2 \cdot 4}

z = \frac{- 2 + 2 13}{2 \cdot 4} : \frac{- 1 + 13}{4}

z = \frac{- 2 - 2 13}{2 \cdot 4} : - \frac{1 + 13}{4}

The solutions to the quadratic equation are:

z = \frac{- 1 + 13}{4}, z = - \frac{1 + 13}{4}

(2 x + 4)^{2} - 5 = 31

x^{2} - 3 (x + 2) + 8 = 0

(3 x - 4) (2 x + 3) = 0

(z + 1)^{2} = - 81

p^{2} - 14 p + 10 = - 8 p

What are the solutions to the equation 4z^2+14z-3=12z ?
The solutions to the equation 4z^2+14z-3=12z are z=(-1+sqrt(13))/4 ,z=-(1+sqrt(13))/4
Find the zeros of 4z^2+14z-3=12z
The zeros of 4z^2+14z-3=12z are z=(-1+sqrt(13))/4 ,z=-(1+sqrt(13))/4