What are the solutions to the equation 9a^2+46a=-5 ?

The solutions to the equation 9a^2+46a=-5 are a=-1/9 ,a=-5

Find the zeros of 9a^2+46a=-5

The zeros of 9a^2+46a=-5 are a=-1/9 ,a=-5

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9 a^{2} + 46 a = - 5

a = - \frac{1}{9}, a = - 5

Decimal Notation

a = - 0.11111 \dots, a = - 5

Solution steps

9 a^{2} + 46 a = - 5

Move

5

to the left side

9 a^{2} + 46 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 46 \pm 4 6 ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

4 6^{2} - 4 \cdot 9 \cdot 5 = 44

a_{1, 2} = \frac{- 46 \pm 44}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 46 + 44}{2 \cdot 9}, a_{2} = \frac{- 46 - 44}{2 \cdot 9}

a = \frac{- 46 + 44}{2 \cdot 9} : - \frac{1}{9}

a = \frac{- 46 - 44}{2 \cdot 9} : - 5

The solutions to the quadratic equation are:

a = - \frac{1}{9}, a = - 5

- 6 + 3 x^{2} = - 39

2 x^{2} - x - 28 = 0

100 x^{2} = 0

8 x^{2} - 43 x - 30 = 0

\frac{1}{2} (c - 8)^{2} = 8

What are the solutions to the equation 9a^2+46a=-5 ?
The solutions to the equation 9a^2+46a=-5 are a=-1/9 ,a=-5
Find the zeros of 9a^2+46a=-5
The zeros of 9a^2+46a=-5 are a=-1/9 ,a=-5