What are the solutions to the equation 32x^2+50=80x ?

The solutions to the equation 32x^2+50=80x are x= 5/4

Find the zeros of 32x^2+50=80x

The zeros of 32x^2+50=80x are x= 5/4

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32 x^{2} + 50 = 80 x

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

32 x^{2} + 50 = 80 x

Move

80 x

to the left side

32 x^{2} + 50 - 80 x = 0

Write in the standard form

a x^{2} + b x + c = 0

32 x^{2} - 80 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 32 \cdot 50}{2 \cdot 32}

(- 80)^{2} - 4 \cdot 32 \cdot 50 = 0

x_{1, 2} = \frac{- ( - 80 ) \pm 0}{2 \cdot 32}

x = \frac{- ( - 80 )}{2 \cdot 32}

\frac{- ( - 80 )}{2 \cdot 32} = \frac{5}{4}

x = \frac{5}{4}

The solution to the quadratic equation is:

x = \frac{5}{4}

2 0^{2} = x^{2} + x^{2}

9 y + 5 y^{2} = 18

7 x^{2} + 2 x = x + 5 x^{2}

5 x^{2} + 1 = 9

5 x^{2} + 1 = 1

What are the solutions to the equation 32x^2+50=80x ?
The solutions to the equation 32x^2+50=80x are x= 5/4
Find the zeros of 32x^2+50=80x
The zeros of 32x^2+50=80x are x= 5/4