What are the solutions to the equation (6t+1)^2+3=0 ?

The solutions to the equation (6t+1)^2+3=0 are t=-1/6+i(sqrt(3))/6 ,t=-1/6-i(sqrt(3))/6

Find the zeros of (6t+1)^2+3=0

The zeros of (6t+1)^2+3=0 are t=-1/6+i(sqrt(3))/6 ,t=-1/6-i(sqrt(3))/6

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(6 t + 1)^{2} + 3 = 0

t = - \frac{1}{6} + i \frac{3}{6}, t = - \frac{1}{6} - i \frac{3}{6}

Solution steps

(6 t + 1)^{2} + 3 = 0

Move

3

to the right side

(6 t + 1)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 t + 1 = - 3 : t = - \frac{1}{6} + i \frac{3}{6}

Solve

6 t + 1 = - - 3 : t = - \frac{1}{6} - i \frac{3}{6}

The solutions to the quadratic equation are:

t = - \frac{1}{6} + i \frac{3}{6}, t = - \frac{1}{6} - i \frac{3}{6}

0.2 x^{2} - 0.4 x - 0.2 = 0

x, f (x + 1) = 4 x^{2} + 3 x - 2

36 v^{2} + 2 = 6

x (x - 2) = - 1

16 x^{2} + 25 = - 40 x

What are the solutions to the equation (6t+1)^2+3=0 ?
The solutions to the equation (6t+1)^2+3=0 are t=-1/6+i(sqrt(3))/6 ,t=-1/6-i(sqrt(3))/6
Find the zeros of (6t+1)^2+3=0
The zeros of (6t+1)^2+3=0 are t=-1/6+i(sqrt(3))/6 ,t=-1/6-i(sqrt(3))/6