What are the solutions to the equation c^2-14c+49=0 ?

The solutions to the equation c^2-14c+49=0 are c=7

Find the zeros of c^2-14c+49=0

The zeros of c^2-14c+49=0 are c=7

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c^{2} - 14 c + 49 = 0

c = 7

Solution steps

c^{2} - 14 c + 49 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

c_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

c = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

c = 7

The solution to the quadratic equation is:

c = 7

x^{2} - 9 x + 4 = 24

\frac{6 ^{3}}{7 ^{2}} = x^{2}

- 4 - 5 v^{2} = - 364

3 x^{2} + 2 x = 11

6 x^{2} + 3 x - 630 = 0

What are the solutions to the equation c^2-14c+49=0 ?
The solutions to the equation c^2-14c+49=0 are c=7
Find the zeros of c^2-14c+49=0
The zeros of c^2-14c+49=0 are c=7