What are the solutions to the equation n^2-n=6 ?

The solutions to the equation n^2-n=6 are n=3,n=-2

Find the zeros of n^2-n=6

The zeros of n^2-n=6 are n=3,n=-2

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n^{2} - n = 6

n = 3, n = - 2

Solution steps

n^{2} - n = 6

Move

6

to the left side

n^{2} - n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

n_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, n_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

n = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

n = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

n = 3, n = - 2

x^{2} - 14 x - 4 = 0

54 = 0.04 x^{2} + 0.2 x + 12

x^{2} - 6 x - 2

x^{2} - 6 x - 6

t^{2} - 4 t - 2 = 0

What are the solutions to the equation n^2-n=6 ?
The solutions to the equation n^2-n=6 are n=3,n=-2
Find the zeros of n^2-n=6
The zeros of n^2-n=6 are n=3,n=-2