What are the solutions to the equation (3x-6)^2+2(3x-6)-8=0 ?

The solutions to the equation (3x-6)^2+2(3x-6)-8=0 are x= 8/3 ,x= 2/3

Find the zeros of (3x-6)^2+2(3x-6)-8=0

The zeros of (3x-6)^2+2(3x-6)-8=0 are x= 8/3 ,x= 2/3

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(3 x - 6)^{2} + 2 (3 x - 6) - 8 = 0

x = \frac{8}{3}, x = \frac{2}{3}

Decimal Notation

x = 2.66666 \dots, x = 0.66666 \dots

Solution steps

(3 x - 6)^{2} + 2 (3 x - 6) - 8 = 0

Expand

(3 x - 6)^{2} + 2 (3 x - 6) - 8 : 9 x^{2} - 30 x + 16

9 x^{2} - 30 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

(- 30)^{2} - 4 \cdot 9 \cdot 16 = 18

x_{1, 2} = \frac{- ( - 30 ) \pm 18}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 18}{2 \cdot 9}, x_{2} = \frac{- ( - 30 ) - 18}{2 \cdot 9}

x = \frac{- ( - 30 ) + 18}{2 \cdot 9} : \frac{8}{3}

x = \frac{- ( - 30 ) - 18}{2 \cdot 9} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = \frac{2}{3}

7 - 5 x = 3 x^{2}

2 (x + 6)^{2} = 8

- x^{2} + 18 x - 22 = - 2

y^{2} + y = 6

9 x^{2} + 18 x + 10 = 0

What are the solutions to the equation (3x-6)^2+2(3x-6)-8=0 ?
The solutions to the equation (3x-6)^2+2(3x-6)-8=0 are x= 8/3 ,x= 2/3
Find the zeros of (3x-6)^2+2(3x-6)-8=0
The zeros of (3x-6)^2+2(3x-6)-8=0 are x= 8/3 ,x= 2/3