What are the solutions to the equation 21x^2=10-x ?

The solutions to the equation 21x^2=10-x are x= 2/3 ,x=-5/7

Find the zeros of 21x^2=10-x

The zeros of 21x^2=10-x are x= 2/3 ,x=-5/7

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21 x^{2} = 10 - x

x = \frac{2}{3}, x = - \frac{5}{7}

Decimal Notation

x = 0.66666 \dots, x = - 0.71428 \dots

Solution steps

21 x^{2} = 10 - x

Move

x

to the left side

21 x^{2} + x = 10

Move

10

to the left side

21 x^{2} + x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 21 ( - 10 )}{2 \cdot 21}

1^{2} - 4 \cdot 21 (- 10) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 21}, x_{2} = \frac{- 1 - 29}{2 \cdot 21}

x = \frac{- 1 + 29}{2 \cdot 21} : \frac{2}{3}

x = \frac{- 1 - 29}{2 \cdot 21} : - \frac{5}{7}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{5}{7}

x^{2} - 8 x + 19

x, (x - C^{1})^{2} + y^{2} = C^{2}

x^{2} + 3 x^{2} - 4 x - 12 = 0

- 2 = x^{2} + 2 x

v, F = \frac{z M v ^{2}}{r}

What are the solutions to the equation 21x^2=10-x ?
The solutions to the equation 21x^2=10-x are x= 2/3 ,x=-5/7
Find the zeros of 21x^2=10-x
The zeros of 21x^2=10-x are x= 2/3 ,x=-5/7