What are the solutions to the equation 0=2x^2-10x+12 ?

The solutions to the equation 0=2x^2-10x+12 are x=3,x=2

Find the zeros of 0=2x^2-10x+12

The zeros of 0=2x^2-10x+12 are x=3,x=2

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0 = 2 x^{2} - 10 x + 12

x = 3, x = 2

Solution steps

0 = 2 x^{2} - 10 x + 12

Switch sides

2 x^{2} - 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 12}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 12 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2}{2 \cdot 2} : 3

x = \frac{- ( - 10 ) - 2}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

4 x^{2} - 2 x + 25 = 0

3 x^{2} + 19 x - 40 = 0

x^{2} + 5 x + 3 = 0

8 x^{2} + 8 x - 6 = 0

4 x^{2} - 4 x + 17 = 0

What are the solutions to the equation 0=2x^2-10x+12 ?
The solutions to the equation 0=2x^2-10x+12 are x=3,x=2
Find the zeros of 0=2x^2-10x+12
The zeros of 0=2x^2-10x+12 are x=3,x=2