What are the solutions to the equation 2x^2+x-1/2 =0 ?

The solutions to the equation 2x^2+x-1/2 =0 are x=(-1+sqrt(5))/4 ,x=-(1+sqrt(5))/4

Find the zeros of 2x^2+x-1/2 =0

The zeros of 2x^2+x-1/2 =0 are x=(-1+sqrt(5))/4 ,x=-(1+sqrt(5))/4

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2 x^{2} + x - \frac{1}{2} = 0

x = \frac{- 1 + 5}{4}, x = - \frac{1 + 5}{4}

Decimal Notation

x = 0.30901 \dots, x = - 0.80901 \dots

Solution steps

2 x^{2} + x - \frac{1}{2} = 0

Multiply both sides by

2

4 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 1) = 25

x_{1, 2} = \frac{- 2 \pm 2 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 5}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 5}{2 \cdot 4}

x = \frac{- 2 + 2 5}{2 \cdot 4} : \frac{- 1 + 5}{4}

x = \frac{- 2 - 2 5}{2 \cdot 4} : - \frac{1 + 5}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{4}, x = - \frac{1 + 5}{4}

6^{2} + 1 1^{2} = c^{2}

\frac{3 x ^{2}}{2} = 150

e^{2} + 6 e + 8 = 0

y, x y^{2} = 1

4 x^{2} + 6 = 14

What are the solutions to the equation 2x^2+x-1/2 =0 ?
The solutions to the equation 2x^2+x-1/2 =0 are x=(-1+sqrt(5))/4 ,x=-(1+sqrt(5))/4
Find the zeros of 2x^2+x-1/2 =0
The zeros of 2x^2+x-1/2 =0 are x=(-1+sqrt(5))/4 ,x=-(1+sqrt(5))/4