What are the solutions to the equation 6^2+11^2=c^2 ?

The solutions to the equation 6^2+11^2=c^2 are c=sqrt(157),c=-sqrt(157)

Find the zeros of 6^2+11^2=c^2

The zeros of 6^2+11^2=c^2 are c=sqrt(157),c=-sqrt(157)

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6^{2} + 1 1^{2} = c^{2}

c = 157, c = - 157

Decimal Notation

c = 12.52996 \dots, c = - 12.52996 \dots

Solution steps

6^{2} + 1 1^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 1 1^{2}

Simplify

6^{2} + 1 1^{2} : 157

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 157, c = - 157

\frac{3 x ^{2}}{2} = 150

e^{2} + 6 e + 8 = 0

y, x y^{2} = 1

4 x^{2} + 6 = 14

t^{2} - 12 = 0

What are the solutions to the equation 6^2+11^2=c^2 ?
The solutions to the equation 6^2+11^2=c^2 are c=sqrt(157),c=-sqrt(157)
Find the zeros of 6^2+11^2=c^2
The zeros of 6^2+11^2=c^2 are c=sqrt(157),c=-sqrt(157)