What are the solutions to the equation t^2-12=0 ?

The solutions to the equation t^2-12=0 are t=2sqrt(3),t=-2sqrt(3)

Find the zeros of t^2-12=0

The zeros of t^2-12=0 are t=2sqrt(3),t=-2sqrt(3)

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t^{2} - 12 = 0

t = 23, t = - 23

Decimal Notation

t = 3.46410 \dots, t = - 3.46410 \dots

Solution steps

t^{2} - 12 = 0

Move

12

to the right side

t^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 12, t = - 12

12 = 23

- 12 = - 23

t = 23, t = - 23

- x^{2} - 2 x + 4

3 b^{2} - 10 b - 8 = 0

12 - 4 x - x^{2} = 0

a, a^{2} - 2 ab + b^{2} = 0

27 x^{2} = 3

What are the solutions to the equation t^2-12=0 ?
The solutions to the equation t^2-12=0 are t=2sqrt(3),t=-2sqrt(3)
Find the zeros of t^2-12=0
The zeros of t^2-12=0 are t=2sqrt(3),t=-2sqrt(3)