What are the solutions to the equation solvefor a,a^2-2ab+b^2=0 ?

The solutions to the equation solvefor a,a^2-2ab+b^2=0 are a=b

Find the zeros of solvefor a,a^2-2ab+b^2=0

The zeros of solvefor a,a^2-2ab+b^2=0 are a=b

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solve for

a, a^{2} - 2 ab + b^{2} = 0

a = b

Solution steps

a^{2} - 2 ab + b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 2 ba + b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 b ) \pm ( - 2 b ) ^{2} - 4 \cdot 1 \cdot b ^{2}}{2 \cdot 1}

(- 2 b)^{2} - 4 \cdot 1 \cdot b^{2} = 0

a_{1, 2} = \frac{- ( - 2 b ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 2 b )}{2 \cdot 1}

Simplify

\frac{- ( - 2 b )}{2 \cdot 1} : b

a = b

The solution to the quadratic equation is:

a = b

27 x^{2} = 3

- 5 x^{2} + 25 x = - 120

r^{2} - 4 r - 91 + 7 = 0

3 x^{2} - 5 x - 16 = 0

4 x^{2} - 28 x + 49

What are the solutions to the equation solvefor a,a^2-2ab+b^2=0 ?
The solutions to the equation solvefor a,a^2-2ab+b^2=0 are a=b
Find the zeros of solvefor a,a^2-2ab+b^2=0
The zeros of solvefor a,a^2-2ab+b^2=0 are a=b