What are the solutions to the equation 3x^2-5x-16=0 ?

The solutions to the equation 3x^2-5x-16=0 are x=(5+sqrt(217))/6 ,x=(5-sqrt(217))/6

Find the zeros of 3x^2-5x-16=0

The zeros of 3x^2-5x-16=0 are x=(5+sqrt(217))/6 ,x=(5-sqrt(217))/6

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3 x^{2} - 5 x - 16 = 0

x = \frac{5 + 217}{6}, x = \frac{5 - 217}{6}

Decimal Notation

x = 3.28848 \dots, x = - 1.62181 \dots

Solution steps

3 x^{2} - 5 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 16) = 217

x_{1, 2} = \frac{- ( - 5 ) \pm 217}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 217}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 217}{2 \cdot 3}

x = \frac{- ( - 5 ) + 217}{2 \cdot 3} : \frac{5 + 217}{6}

x = \frac{- ( - 5 ) - 217}{2 \cdot 3} : \frac{5 - 217}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 217}{6}, x = \frac{5 - 217}{6}

4 x^{2} - 28 x + 49

m^{2} - 5 m - 14 = 0

5 n^{2} - 14 = - 6

2 x^{2} + 6 x = 3 + x

x^{2} - x = 6

What are the solutions to the equation 3x^2-5x-16=0 ?
The solutions to the equation 3x^2-5x-16=0 are x=(5+sqrt(217))/6 ,x=(5-sqrt(217))/6
Find the zeros of 3x^2-5x-16=0
The zeros of 3x^2-5x-16=0 are x=(5+sqrt(217))/6 ,x=(5-sqrt(217))/6