What are the solutions to the equation 5n^2-14=-6 ?

The solutions to the equation 5n^2-14=-6 are n=(2sqrt(2))/(sqrt(5)),n=-(2sqrt(2))/(sqrt(5))

Find the zeros of 5n^2-14=-6

The zeros of 5n^2-14=-6 are n=(2sqrt(2))/(sqrt(5)),n=-(2sqrt(2))/(sqrt(5))

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5 n^{2} - 14 = - 6

n = \frac{2 2}{5}, n = - \frac{2 2}{5}

Decimal Notation

n = 1.26491 \dots, n = - 1.26491 \dots

Solution steps

5 n^{2} - 14 = - 6

Move

14

to the right side

5 n^{2} = 8

Divide both sides by

5

n^{2} = \frac{8}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{8}{5}, n = - \frac{8}{5}

\frac{8}{5} = \frac{2 2}{5}

- \frac{8}{5} = - \frac{2 2}{5}

n = \frac{2 2}{5}, n = - \frac{2 2}{5}

2 x^{2} + 6 x = 3 + x

x^{2} - x = 6

7 x^{2} + 5 x = - 2

- 200 x^{2} + 200 x - 40 = 0

x^{2} = 6^{2} + 5^{2}

What are the solutions to the equation 5n^2-14=-6 ?
The solutions to the equation 5n^2-14=-6 are n=(2sqrt(2))/(sqrt(5)),n=-(2sqrt(2))/(sqrt(5))
Find the zeros of 5n^2-14=-6
The zeros of 5n^2-14=-6 are n=(2sqrt(2))/(sqrt(5)),n=-(2sqrt(2))/(sqrt(5))