What are the solutions to the equation 7x^2+5x=-2 ?

The solutions to the equation 7x^2+5x=-2 are x=-5/14+i(sqrt(31))/(14),x=-5/14-i(sqrt(31))/(14)

Find the zeros of 7x^2+5x=-2

The zeros of 7x^2+5x=-2 are x=-5/14+i(sqrt(31))/(14),x=-5/14-i(sqrt(31))/(14)

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7 x^{2} + 5 x = - 2

x = - \frac{5}{14} + i \frac{31}{14}, x = - \frac{5}{14} - i \frac{31}{14}

Solution steps

7 x^{2} + 5 x = - 2

Move

2

to the left side

7 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

5^{2} - 4 \cdot 7 \cdot 2 : 31 i

x_{1, 2} = \frac{- 5 \pm 31 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 5 + 31 i}{2 \cdot 7}, x_{2} = \frac{- 5 - 31 i}{2 \cdot 7}

x = \frac{- 5 + 31 i}{2 \cdot 7} : - \frac{5}{14} + i \frac{31}{14}

x = \frac{- 5 - 31 i}{2 \cdot 7} : - \frac{5}{14} - i \frac{31}{14}

The solutions to the quadratic equation are:

x = - \frac{5}{14} + i \frac{31}{14}, x = - \frac{5}{14} - i \frac{31}{14}

- 200 x^{2} + 200 x - 40 = 0

x^{2} = 6^{2} + 5^{2}

10 x^{2} - 24 x - 19 = - 9 x^{2} - 24 x

4 a^{2} - 100 = 0

2 x^{2} + 5 x - 33 = 0

What are the solutions to the equation 7x^2+5x=-2 ?
The solutions to the equation 7x^2+5x=-2 are x=-5/14+i(sqrt(31))/(14),x=-5/14-i(sqrt(31))/(14)
Find the zeros of 7x^2+5x=-2
The zeros of 7x^2+5x=-2 are x=-5/14+i(sqrt(31))/(14),x=-5/14-i(sqrt(31))/(14)