What are the solutions to the equation -(q^2)/9+3q-2=0 ?

The solutions to the equation -(q^2)/9+3q-2=0 are q=(27-3sqrt(73))/2 ,q=(27+3sqrt(73))/2

Find the zeros of -(q^2)/9+3q-2=0

The zeros of -(q^2)/9+3q-2=0 are q=(27-3sqrt(73))/2 ,q=(27+3sqrt(73))/2

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- \frac{q ^{2}}{9} + 3 q - 2 = 0

q = \frac{27 - 3 73}{2}, q = \frac{27 + 3 73}{2}

Decimal Notation

q = 0.68399 \dots, q = 26.31600 \dots

Solution steps

- \frac{q ^{2}}{9} + 3 q - 2 = 0

Multiply both sides by

9

- q^{2} + 27 q - 18 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

2 7^{2} - 4 (- 1) (- 18) = 373

q_{1, 2} = \frac{- 27 \pm 3 73}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- 27 + 3 73}{2 ( - 1 )}, q_{2} = \frac{- 27 - 3 73}{2 ( - 1 )}

q = \frac{- 27 + 3 73}{2 ( - 1 )} : \frac{27 - 3 73}{2}

q = \frac{- 27 - 3 73}{2 ( - 1 )} : \frac{27 + 3 73}{2}

The solutions to the quadratic equation are:

q = \frac{27 - 3 73}{2}, q = \frac{27 + 3 73}{2}

\frac{2 x ^{2} - 3}{4} = 5

x, 4 x^{2} + k x + 9 = 0

15 - x^{2} = 0

7 x^{2} + 58 x + 63 = 0

- 4 x^{2} - 9 x - 2 = 0

What are the solutions to the equation -(q^2)/9+3q-2=0 ?
The solutions to the equation -(q^2)/9+3q-2=0 are q=(27-3sqrt(73))/2 ,q=(27+3sqrt(73))/2
Find the zeros of -(q^2)/9+3q-2=0
The zeros of -(q^2)/9+3q-2=0 are q=(27-3sqrt(73))/2 ,q=(27+3sqrt(73))/2