What are the solutions to the equation 7x^2+58x+63=0 ?

The solutions to the equation 7x^2+58x+63=0 are x=-9/7 ,x=-7

Find the zeros of 7x^2+58x+63=0

The zeros of 7x^2+58x+63=0 are x=-9/7 ,x=-7

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7 x^{2} + 58 x + 63 = 0

x = - \frac{9}{7}, x = - 7

Decimal Notation

x = - 1.28571 \dots, x = - 7

Solution steps

7 x^{2} + 58 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 58 \pm 5 8 ^{2} - 4 \cdot 7 \cdot 63}{2 \cdot 7}

5 8^{2} - 4 \cdot 7 \cdot 63 = 40

x_{1, 2} = \frac{- 58 \pm 40}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 58 + 40}{2 \cdot 7}, x_{2} = \frac{- 58 - 40}{2 \cdot 7}

x = \frac{- 58 + 40}{2 \cdot 7} : - \frac{9}{7}

x = \frac{- 58 - 40}{2 \cdot 7} : - 7

The solutions to the quadratic equation are:

x = - \frac{9}{7}, x = - 7

- 4 x^{2} - 9 x - 2 = 0

3 q^{2} - 100 q + 750 = 0

- x^{2} - 18 x + 20 = 0

(2 x + 3)^{2} = - 6

(3 x + 1) (1 - x) - 3 (x + 1)^{2} = x - 3

What are the solutions to the equation 7x^2+58x+63=0 ?
The solutions to the equation 7x^2+58x+63=0 are x=-9/7 ,x=-7
Find the zeros of 7x^2+58x+63=0
The zeros of 7x^2+58x+63=0 are x=-9/7 ,x=-7