What are the solutions to the equation x^2-2x-5=30 ?

The solutions to the equation x^2-2x-5=30 are x=7,x=-5

Find the zeros of x^2-2x-5=30

The zeros of x^2-2x-5=30 are x=7,x=-5

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x^{2} - 2 x - 5 = 30

x = 7, x = - 5

Solution steps

x^{2} - 2 x - 5 = 30

Move

30

to the left side

x^{2} - 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12}{2 \cdot 1} : 7

x = \frac{- ( - 2 ) - 12}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

b^{2} - 9 b + 20 = 0

49 x^{2} = 121

x^{2} - 5 x - 3 = 0

x^{2} - 9 x + 20 = 0

s^{2} = - 4

What are the solutions to the equation x^2-2x-5=30 ?
The solutions to the equation x^2-2x-5=30 are x=7,x=-5
Find the zeros of x^2-2x-5=30
The zeros of x^2-2x-5=30 are x=7,x=-5