What are the solutions to the equation 6(x-12)(x-8)=840 ?

The solutions to the equation 6(x-12)(x-8)=840 are x=22,x=-2

Find the zeros of 6(x-12)(x-8)=840

The zeros of 6(x-12)(x-8)=840 are x=22,x=-2

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6 (x - 12) (x - 8) = 840

x = 22, x = - 2

Solution steps

6 (x - 12) (x - 8) = 840

Expand

6 (x - 12) (x - 8) : 6 x^{2} - 120 x + 576

6 x^{2} - 120 x + 576 = 840

Move

840

to the left side

6 x^{2} - 120 x - 264 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 6 ( - 264 )}{2 \cdot 6}

(- 120)^{2} - 4 \cdot 6 (- 264) = 144

x_{1, 2} = \frac{- ( - 120 ) \pm 144}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 120 ) + 144}{2 \cdot 6}, x_{2} = \frac{- ( - 120 ) - 144}{2 \cdot 6}

x = \frac{- ( - 120 ) + 144}{2 \cdot 6} : 22

x = \frac{- ( - 120 ) - 144}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

x = 22, x = - 2

2 x^{2} - 19 x + 42 = 0

x^{2} - 3 (x + 4) = - 2 x

x^{2} + 5 x - 9 = 0

x^{2} - 18 x - 7 = 0

15 x - 10 = 6 x (x - 2) + (- x + 3)

What are the solutions to the equation 6(x-12)(x-8)=840 ?
The solutions to the equation 6(x-12)(x-8)=840 are x=22,x=-2
Find the zeros of 6(x-12)(x-8)=840
The zeros of 6(x-12)(x-8)=840 are x=22,x=-2