What are the solutions to the equation 5x^2+20x-85=0 ?

The solutions to the equation 5x^2+20x-85=0 are x=-2+sqrt(21),x=-2-sqrt(21)

Find the zeros of 5x^2+20x-85=0

The zeros of 5x^2+20x-85=0 are x=-2+sqrt(21),x=-2-sqrt(21)

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5 x^{2} + 20 x - 85 = 0

x = - 2 + 21, x = - 2 - 21

Decimal Notation

x = 2.58257 \dots, x = - 6.58257 \dots

Solution steps

5 x^{2} + 20 x - 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 ( - 85 )}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 (- 85) = 1021

x_{1, 2} = \frac{- 20 \pm 10 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 10 21}{2 \cdot 5}, x_{2} = \frac{- 20 - 10 21}{2 \cdot 5}

x = \frac{- 20 + 10 21}{2 \cdot 5} : - 2 + 21

x = \frac{- 20 - 10 21}{2 \cdot 5} : - 2 - 21

The solutions to the quadratic equation are:

x = - 2 + 21, x = - 2 - 21

9 x^{2} - c^{2} = 0

0.0169 = c^{2}

x, x^{2} + 1 = y^{3} - 1

2 x^{2} + x - 10 = 0

u^{2} - 3 u = - 54

What are the solutions to the equation 5x^2+20x-85=0 ?
The solutions to the equation 5x^2+20x-85=0 are x=-2+sqrt(21),x=-2-sqrt(21)
Find the zeros of 5x^2+20x-85=0
The zeros of 5x^2+20x-85=0 are x=-2+sqrt(21),x=-2-sqrt(21)