What are the solutions to the equation 2a^2-2a=12 ?

The solutions to the equation 2a^2-2a=12 are a=3,a=-2

Find the zeros of 2a^2-2a=12

The zeros of 2a^2-2a=12 are a=3,a=-2

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2 a^{2} - 2 a = 12

a = 3, a = - 2

Solution steps

2 a^{2} - 2 a = 12

Move

12

to the left side

2 a^{2} - 2 a - 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 12) = 10

a_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 2}, a_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 2}

a = \frac{- ( - 2 ) + 10}{2 \cdot 2} : 3

a = \frac{- ( - 2 ) - 10}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

a = 3, a = - 2

x (x + 35) = - 66

(x^{2} - 5 x) = 6

28 = 5 r + 3 r^{2}

x, 9 x^{2} + 36 y^{2} = 0

2 x^{2} + 4 x + 38 = - 6

What are the solutions to the equation 2a^2-2a=12 ?
The solutions to the equation 2a^2-2a=12 are a=3,a=-2
Find the zeros of 2a^2-2a=12
The zeros of 2a^2-2a=12 are a=3,a=-2