What are the solutions to the equation 0=-6c^2+30c+300 ?

The solutions to the equation 0=-6c^2+30c+300 are c=-5,c=10

Find the zeros of 0=-6c^2+30c+300

The zeros of 0=-6c^2+30c+300 are c=-5,c=10

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0 = - 6 c^{2} + 30 c + 300

c = - 5, c = 10

Solution steps

0 = - 6 c^{2} + 30 c + 300

Switch sides

- 6 c^{2} + 30 c + 300 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 6 ) \cdot 300}{2 ( - 6 )}

3 0^{2} - 4 (- 6) \cdot 300 = 90

c_{1, 2} = \frac{- 30 \pm 90}{2 ( - 6 )}

Separate the solutions

c_{1} = \frac{- 30 + 90}{2 ( - 6 )}, c_{2} = \frac{- 30 - 90}{2 ( - 6 )}

c = \frac{- 30 + 90}{2 ( - 6 )} : - 5

c = \frac{- 30 - 90}{2 ( - 6 )} : 10

The solutions to the quadratic equation are:

c = - 5, c = 10

1 7^{2} = x^{2} + 5^{2}

250 = 50 x - 300 - 0.01 x^{2}

5 x^{2} + 70 = 50 x

3 h^{2} - 5 h + 2 = 0

(x - 1)^{2} = - 3

What are the solutions to the equation 0=-6c^2+30c+300 ?
The solutions to the equation 0=-6c^2+30c+300 are c=-5,c=10
Find the zeros of 0=-6c^2+30c+300
The zeros of 0=-6c^2+30c+300 are c=-5,c=10