What are the solutions to the equation -4=-4x^2-6x ?

The solutions to the equation -4=-4x^2-6x are x=-2,x= 1/2

Find the zeros of -4=-4x^2-6x

The zeros of -4=-4x^2-6x are x=-2,x= 1/2

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- 4 = - 4 x^{2} - 6 x

x = - 2, x = \frac{1}{2}

Decimal Notation

x = - 2, x = 0.5

Solution steps

- 4 = - 4 x^{2} - 6 x

Switch sides

- 4 x^{2} - 6 x = - 4

Move

4

to the left side

- 4 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

(- 6)^{2} - 4 (- 4) \cdot 4 = 10

x_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10}{2 ( - 4 )}, x_{2} = \frac{- ( - 6 ) - 10}{2 ( - 4 )}

x = \frac{- ( - 6 ) + 10}{2 ( - 4 )} : - 2

x = \frac{- ( - 6 ) - 10}{2 ( - 4 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{1}{2}

2 x^{2} - \frac{1}{32} = 0

t, 7 = 16 - 9.8 t^{2}

x^{2} + 3 x - 15 = - 4

2 x (x - 2) = x + 3

x, - x^{2} + 2 x = y

What are the solutions to the equation -4=-4x^2-6x ?
The solutions to the equation -4=-4x^2-6x are x=-2,x= 1/2
Find the zeros of -4=-4x^2-6x
The zeros of -4=-4x^2-6x are x=-2,x= 1/2