What are the solutions to the equation -9x^2+4x=0 ?

The solutions to the equation -9x^2+4x=0 are x=0,x= 4/9

Find the zeros of -9x^2+4x=0

The zeros of -9x^2+4x=0 are x=0,x= 4/9

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- 9 x^{2} + 4 x = 0

x = 0, x = \frac{4}{9}

Decimal Notation

x = 0, x = 0.44444 \dots

Solution steps

- 9 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 9 ) \cdot 0}{2 ( - 9 )}

4^{2} - 4 (- 9) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 9 )}, x_{2} = \frac{- 4 - 4}{2 ( - 9 )}

x = \frac{- 4 + 4}{2 ( - 9 )} : 0

x = \frac{- 4 - 4}{2 ( - 9 )} : \frac{4}{9}

The solutions to the quadratic equation are:

x = 0, x = \frac{4}{9}

y, 0 = 3 y - 2 x y - 3 y^{2}

x, a x^{2} + b x = - c

4 x^{2} + 10 x - 15 = 0

x^{2} - 10 \cdot x + 24 = 0

60 t + 1.05 t^{2} = 800

What are the solutions to the equation -9x^2+4x=0 ?
The solutions to the equation -9x^2+4x=0 are x=0,x= 4/9
Find the zeros of -9x^2+4x=0
The zeros of -9x^2+4x=0 are x=0,x= 4/9