What are the solutions to the equation 10x^2+11x-3=0 ?

The solutions to the equation 10x^2+11x-3=0 are x=(-11+sqrt(241))/(20),x=(-11-sqrt(241))/(20)

Find the zeros of 10x^2+11x-3=0

The zeros of 10x^2+11x-3=0 are x=(-11+sqrt(241))/(20),x=(-11-sqrt(241))/(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} + 11 x - 3 = 0

x = \frac{- 11 + 241}{20}, x = \frac{- 11 - 241}{20}

Decimal Notation

x = 0.22620 \dots, x = - 1.32620 \dots

Solution steps

10 x^{2} + 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 10 ( - 3 )}{2 \cdot 10}

1 1^{2} - 4 \cdot 10 (- 3) = 241

x_{1, 2} = \frac{- 11 \pm 241}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 11 + 241}{2 \cdot 10}, x_{2} = \frac{- 11 - 241}{2 \cdot 10}

x = \frac{- 11 + 241}{2 \cdot 10} : \frac{- 11 + 241}{20}

x = \frac{- 11 - 241}{2 \cdot 10} : \frac{- 11 - 241}{20}

The solutions to the quadratic equation are:

x = \frac{- 11 + 241}{20}, x = \frac{- 11 - 241}{20}

x^{2} - \frac{1}{8} x + 23 = 100

2 x (5 - x) = x^{2} + 3

8 + x^{2} + 3 x = 0

- x^{2} + 6 x - 11 = 0

(x + 2) (x + 9) = 0

What are the solutions to the equation 10x^2+11x-3=0 ?
The solutions to the equation 10x^2+11x-3=0 are x=(-11+sqrt(241))/(20),x=(-11-sqrt(241))/(20)
Find the zeros of 10x^2+11x-3=0
The zeros of 10x^2+11x-3=0 are x=(-11+sqrt(241))/(20),x=(-11-sqrt(241))/(20)