What are the solutions to the equation n(n-3)=54 ?

The solutions to the equation n(n-3)=54 are n=9,n=-6

Find the zeros of n(n-3)=54

The zeros of n(n-3)=54 are n=9,n=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n (n - 3) = 54

n = 9, n = - 6

Solution steps

n (n - 3) = 54

Expand

n (n - 3) : n^{2} - 3 n

n^{2} - 3 n = 54

Move

54

to the left side

n^{2} - 3 n - 54 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 54) = 15

n_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 1}

n = \frac{- ( - 3 ) + 15}{2 \cdot 1} : 9

n = \frac{- ( - 3 ) - 15}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 9, n = - 6

n (n - 3) = 70

5 x^{2} = 81

5 x^{2} = 12

- 15 x^{2} - 7 x + 2 = 0

3 (x - 3) (x + 4) = 0

What are the solutions to the equation n(n-3)=54 ?
The solutions to the equation n(n-3)=54 are n=9,n=-6
Find the zeros of n(n-3)=54
The zeros of n(n-3)=54 are n=9,n=-6