What are the solutions to the equation completesquare 9n^2+79=-18n ?

The solutions to the equation completesquare 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3

Find the zeros of completesquare 9n^2+79=-18n

The zeros of completesquare 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 n^{2} + 79 = - 18 n

n = - 1 + i \frac{70}{3}, n = - 1 - i \frac{70}{3}

Solution steps

9 n^{2} + 79 = - 18 n

Move

79

to the right side

9 n^{2} = - 18 n - 79

Move

18 n

to the left side

9 n^{2} + 18 n = - 79

Divide both sides by

9

\frac{9 n ^{2} + 18 n}{9} = \frac{- 79}{9}

n^{2} + 2 n = - \frac{79}{9}

Rewrite in the form

(x + a)^{2} = b

(n + 1)^{2} = - \frac{70}{9}

For

the solutions are

f (x) = a, - a

Solve

n + 1 = - \frac{70}{9} : n = - 1 + i \frac{70}{3}

Solve

n + 1 = - - \frac{70}{9} : n = - 1 - i \frac{70}{3}

The solutions to the quadratic equation are:

n = - 1 + i \frac{70}{3}, n = - 1 - i \frac{70}{3}

15 x^{2} - 7 x - 4 = 0

3 x - 2 x^{2} = 1

r^{2} = (60)^{2} + (- 11)^{2}

(k + 5)^{2} = 0

3 x^{2} - 8 x - 23 = - 4 x - 9

What are the solutions to the equation completesquare 9n^2+79=-18n ?
The solutions to the equation completesquare 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3
Find the zeros of completesquare 9n^2+79=-18n
The zeros of completesquare 9n^2+79=-18n are n=-1+i(sqrt(70))/3 ,n=-1-i(sqrt(70))/3